6x^2-22x-728=0

Solution for 6x^2-22x-728=0 equation:

6x^2-22x-728=0

a = 6; b = -22; c = -728;
Δ = b2-4ac
Δ = -222-4·6·(-728)
Δ = 17956
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17956}=134$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-134}{2*6}=\frac{-112}{12}
=-9+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+134}{2*6}=\frac{156}{12}
=13
$